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4y^2+12y+364y=0
We add all the numbers together, and all the variables
4y^2+376y=0
a = 4; b = 376; c = 0;
Δ = b2-4ac
Δ = 3762-4·4·0
Δ = 141376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{141376}=376$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(376)-376}{2*4}=\frac{-752}{8} =-94 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(376)+376}{2*4}=\frac{0}{8} =0 $
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